Question

plz help me how to do i simpligy this -2 (index 5 ) √160s^2t^6

Answer 1

plz help

Answer 2

plz i have a huge test tomorrow help

Answer 3

\(\huge -2\sqrt[5]{160s^2t^6}\)

Answer 4

its like that ?

Answer 5

yes

Answer 6

it says simpilfy it how plz help

Answer 7

yeah we can simplify it,

Answer 8

we can pull out some t, and 160

Answer 9

can you show me step by step how to do it

Answer 10

lets work on \(t\) first

\(\huge -2\sqrt[5]{160s^2t^6} \)

\(\huge -2\sqrt[5]{160s^2t^{5+1}} \)

Answer 11

ok

Answer 12

u knw this exponent property :

\(a^{m+n} = a^m.a^n\)

?

Answer 13

yeah

Answer 14

lets work on \(t\) first

\(\huge -2\sqrt[5]{160s^2t^6} \)

\(\huge -2\sqrt[5]{160s^2t^{5+1}} \)

\(\huge -2\sqrt[5]{160s^2t^5t^1} \)

Answer 15

fine ?

Answer 16

nw we can pull out t^5, it becomes t

Answer 17

lets work on \(t\) first

\(\huge -2\sqrt[5]{160s^2t^6} \)

\(\huge -2\sqrt[5]{160s^2t^{5+1}} \)

\(\huge -2t\sqrt[5]{160s^2t^1} \)

Answer 18

why did u pull out t5 why not the whole t6

Answer 19

lets work on \(t\) first

\(\huge -2\sqrt[5]{160s^2t^6} \)

\(\huge -2\sqrt[5]{160s^2t^{5+1}} \)

\(\huge -2\sqrt[5]{160s^2t^5t^1} \)

\(\huge -2t\sqrt[5]{160s^2t^5t} \)

Answer 20

good question :)

Answer 21

:)

Answer 22

we can pull out only in powers of 5, coz the t is under 5th index ha ?

Answer 23

ahh ok thanks go on

Answer 24

so t^5 , when it comes out, becomes t

Answer 25

ok i uderstand

Answer 26

we are half done, lets work on 160

Answer 27

160 = 16 x 10

Answer 28

160 = 16 x 10
160 = 16 x 2 x 5

Answer 29

160 = 16 x 10
160 = 16 x 2 x 5
160 = 4 x 4 x 2 x 5

Answer 30

we trying to see if we can make the exponent 5 , so that we pull out of radical something

Answer 31

ok

Answer 32

160 = 16 x 10
160 = 16 x 2 x 5
160 = 4 x 4 x 2 x 5
\(160 = 2^2 \times 2^2 \times 2 \times 5\)

Answer 33

see any exponent 5 ?

Answer 34

what is exponent sorry i forgot

Answer 35

\(a^m\) : \(m\) is the exponent

Answer 36

exponent is also called power

Answer 37

ok

Answer 38

its the thing on top

Answer 39

i understand

Answer 40

then what

Answer 41

160 = 16 x 10
160 = 16 x 2 x 5
160 = 4 x 4 x 2 x 5
\(160 = 2^2 \times 2^2 \times 2 \times 5\)

Answer 42

do u see , any power = 5

Answer 43

ye 2 2 and 1

Answer 44

160 = 16 x 10
160 = 16 x 2 x 5
160 = 4 x 4 x 2 x 5
\(160 = 2^{2+2+1} \times 5\)

Answer 45

Excelelnt !

Answer 46

160 = 16 x 10
160 = 16 x 2 x 5
160 = 4 x 4 x 2 x 5
\(160 = 2^{2+2+1} \times 5\)
\(160 = 2^5\times5\)

Answer 47

so, lets put this in our original expression

Answer 48

ok

Answer 49

\(\huge -2t\sqrt[5]{160s^2t^5t} \)

Answer 50

\(\huge -2t\sqrt[5]{2^55 s^2t^5t} \)

Answer 51

we can pull 2^5 out of radical, it becomes ?

Answer 52

32?

Answer 53

no, 2^5 out of radical, it becomes just 2

Answer 54

ok

Answer 55

\(\huge -2t \ 2\sqrt[5]{5 s^2t^5t} \)

Answer 56

wait are u on facebook

Answer 57

\(\huge -4t\sqrt[5]{5 s^2t} \)

Answer 58

thats our final simplified expression,

Answer 59

ok thanx

Answer 60

np :)

Answer 61

u dont like facebook

Answer 62

there, t^5 is redundantly coming inside radical, even after we simplified t, plz ignore that :)

Answer 63

oh gimme ur id, il add :)

Answer 64

umarnaveed1@hotmail.com

Answer 65

how old are u