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Mathematics 15 Online
OpenStudy (anonymous):

Please Please Please HELP!? Find the domain and range of the function. Screenshot attached!

OpenStudy (anonymous):

nothing attached

OpenStudy (anonymous):

hey :) are you sure that youve attached the correct thing ?

OpenStudy (anonymous):

domain since there is a square root you have to have under it a non negative number so x+1 => 0

OpenStudy (anonymous):

is the domain

OpenStudy (anonymous):

although you probably need to answer in terms of \(x\) rather than \(x+1\)

OpenStudy (anonymous):

but you can solve \[x+1\geq0\] in one step

OpenStudy (anonymous):

yes .. solve for x now

OpenStudy (anonymous):

are you there ? :)

OpenStudy (anonymous):

ok so the domain is given by x+1 => 0 what is the domain for x then ?

OpenStudy (anonymous):

good

OpenStudy (anonymous):

now for the range - since square root returns positive numbers and there is a minus before it the range will be only negative numbers

OpenStudy (anonymous):

but you can see that you get any negative number using this function so the domain is y<=0

OpenStudy (anonymous):

range range im sorry

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

yes you needed the domain and range and you found them .. you can see them through the graph as well .. no x smaller than -1 and no y larger than 0

OpenStudy (anonymous):

yw:)

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