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OpenStudy (anonymous):
Please Please Please HELP!? Find the domain and range of the function. Screenshot attached!
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OpenStudy (anonymous):
nothing attached
OpenStudy (anonymous):
hey :)
are you sure that youve attached the correct thing ?
OpenStudy (anonymous):
domain since there is a square root you have to have under it a non negative number
so
x+1 => 0
OpenStudy (anonymous):
is the domain
OpenStudy (anonymous):
although you probably need to answer in terms of \(x\) rather than \(x+1\)
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OpenStudy (anonymous):
but you can solve
\[x+1\geq0\] in one step
OpenStudy (anonymous):
yes .. solve for x now
OpenStudy (anonymous):
are you there ? :)
OpenStudy (anonymous):
ok so the domain is given by
x+1 => 0
what is the domain for x then ?
OpenStudy (anonymous):
good
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OpenStudy (anonymous):
now for the range - since square root returns positive numbers
and there is a minus before it
the range will be only negative numbers
OpenStudy (anonymous):
but you can see that you get any negative number using this function so
the domain is
y<=0
OpenStudy (anonymous):
range range im sorry
OpenStudy (anonymous):
:)
OpenStudy (anonymous):
yes you needed the domain and range and you found them ..
you can see them through the graph as well ..
no x smaller than -1
and no y larger than 0
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OpenStudy (anonymous):
yw:)
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