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Physics 15 Online
OpenStudy (anonymous):

If vector A = (-3.0, -4.0) and vector B = (+3.0, -8.0), what is the magnitude of vector C = A -B?

OpenStudy (anonymous):

answers are: a. 144 b. 7.2 c. 13 d. 16

OpenStudy (anonymous):

I think it is 7.2

OpenStudy (ash2326):

\[C=A-B\] Subtract component by component \[C=(-3-(3), -4-(-8))\] \[C=(-6, -12)\] magnitude of C \[|C|=\sqrt{(-6)^2+(-12)^2}\] Could you solve this?

OpenStudy (anonymous):

c is = -6, 4 ?

OpenStudy (anonymous):

because of the -4-(-8)= 4

OpenStudy (ash2326):

oops sorry \[|C|=\sqrt{(-6)^2+(4)^2}\]

OpenStudy (ash2326):

yeah you're right, it's 7.2

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