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Mathematics 12 Online
OpenStudy (anonymous):

what are the intercepts?

OpenStudy (anonymous):

OpenStudy (across):

Have you tried graphing that?

hartnn (hartnn):

what is f(x) when x= 0 ?

OpenStudy (anonymous):

i dont know...

OpenStudy (across):

You have to look for all \(x\) such that \(f(x)=0\).

OpenStudy (anonymous):

f(0)=0+5?

hartnn (hartnn):

yeah, so u got y-intercept = 0+5 = 5

OpenStudy (anonymous):

and isnt (1,8) and intercept too?

hartnn (hartnn):

why do u say so ?

OpenStudy (anonymous):

i dont know, i really dont understand this at all. im supposed to find the domain, the intercepts, the range and if f is continuous on its domain

hartnn (hartnn):

its x-intercept when y=0, and y intercept when x=0 so (1,8) cannot be a intercept

OpenStudy (anonymous):

so the only point is (0,5)?

hartnn (hartnn):

that is y-intercept

OpenStudy (anonymous):

x-int would be x+5=0?

hartnn (hartnn):

u need to see when that function goes to 0

hartnn (hartnn):

yes, so x+5=0 when x= ?

hartnn (hartnn):

also -x+2 = 0 x= ?

OpenStudy (anonymous):

-5

OpenStudy (anonymous):

so (-5,0)

hartnn (hartnn):

yes, also 2,0

OpenStudy (anonymous):

thats for the -x+2?

hartnn (hartnn):

yes. and i think -5 won't be intercept, because the function isn't defined for x=-5

OpenStudy (anonymous):

oh i get it

OpenStudy (anonymous):

how do you graph that?

OpenStudy (anonymous):

hartnn (hartnn):

oh, good u have options!

OpenStudy (anonymous):

yeah but idk which one it is lol

hartnn (hartnn):

put various points , x=1, x=2 , x= -1 and so on anf find f(x), match it with graph

OpenStudy (anonymous):

alright

hartnn (hartnn):

really sorry for late replies.

OpenStudy (anonymous):

it's ok, i got it wrong so i have to do a whole new problem

hartnn (hartnn):

:(

OpenStudy (anonymous):

the graph is pissing me off

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