Solve the logarithmic equation algebraically. Approximate the result to three decimal places. (If there is no solution, enter NO SOLUTION.) log2 x + log2(x − 3) = 2
did you attempt
Yes, but it only confused me. I'm not entirely sure how to start solving the equation.
I tried taking the log2 of both sides to try and get rid of the log2 on the left side of the equation...
use LogAB=LOG A+LOG B
Where A=2X AND B= 2(X-3)
try it out, and let me know how it goes before I give you the solution
2x^2 - 6 = 2
2x^2 = 8 x^2 = 4 x = 2 or x= -2
I tried 2, though and it isn't the right answer. Am I even somewhat close?
nope, it should be 2x*(2x-6)
assuming it is log to base 2 and NOT LOG to base 10 we have 4x^2-12x=2^2 4x^2-12x-4=0
if it is log to base 10 WHICH I THINK IS MORE APPROPRIATE, it should be 4x^2-12x=10^2 4x^2-12x-100=0 which can be reduced to 3x^2-3x-25=0
You have to raise 2 to the second power on the right side?
yes ONLY IF IT IS LOG TO BASE 2, AND IF IT IS LOG TO BASE 10 we have 10^2
Still doesn't make too much sense. :/
well you need to solve the equation , i leave that to you, try to factorize, or use quadratic formula if applicable
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