Question

Question! Anyone wanna guide me through it with details? ⊙_⊙..

Answer 1

hey ..
choose some x values and plug it into the equation and see what the corresponding y values
then plot them on the graph

Answer 2

are you there ?

Answer 3

oh its fine..
so are you trying ?

Answer 4

you should look under the square root
x-2 should be non negative (it is actually the domain of the function)
so x-2 >= 0

x>=2
so you cant choose 0.

Answer 5

equal or above 2

Answer 6

2,3,4,... it might be not integers as well but it will be easier with integers

Answer 7

f(3) = sqrt(3-2) - 3 = sqrt(1) - 3 = 1 -3 = -2

Answer 8

i hope they done with this annoying stuff

Answer 9

yes .. so what is f(4) ?

Answer 10

yes.. but as you see it's not a good number to choose since it isnt easy to plut it on the graph ..

x=3
f(3) = sqrt(3-2) - 3 = sqrt(1) - 3 = 1 -3 = -2
x=2
f(2) = sqrt(2-2) - 3 = sqrt(0) - 3 = 0 -3 = -3
x = 11
f(12) = sqrt(11 - 2) - 3 = 3 - 3 = 0

Answer 11

it's better to choose values so sqrt(x-2) will come out as a nice number to plut

Answer 12

the last row should be f(11) = sqrt(11 - 2) - 3 = 3 - 3 = 0

Answer 13

instead of f(12)

Answer 14

are you there ?

Answer 15

it's fine im here

Answer 16

yes .. we can find more but see if it's enough for you

Answer 17

yes

Answer 18

take x =6
what do you get ?

Answer 19

so.. what is f(6) ?

Answer 20

its good

Answer 21

yes
so now you have 3 points that you can plot on the graph ..
when you plot the graph take into account that 11,0 so you dont put 0 at 10 it should be a little lower than 0 at 10 since you know that 0 is at 11

Answer 22

yes you dont use it .. just remember that the graph is negative before 11

Answer 23

yes

Answer 24

what do you mean ?

Answer 25

you mean that you want to pass a curve through those points ?

Answer 26

http://www.wolframalpha.com/input/?i=sqrt%28x-2%29+-3
it looks like the blue line in the first graph starts at x = 2.

Answer 27

the points are correct but you have to pass a cruve through them
i dont know how accurate it should be

Answer 28

no.. as i said the graph is negative before x=11..

Answer 29

a little more like this

Answer 30

its hard to do it really accurately by hand
especially using computer

Answer 31

are you there ?

Answer 32

you are not stupid at all
i hope that it helps you to understand.. i want to see you do questions by yourself eventually :)

Answer 33

yes

Answer 34

yes!!

Answer 35

what do you mean by describe

Answer 36

isnt saying what the domain and range enough ?

Answer 37

maybe you should say as well that the domain is based on the independent variable x
and the range is based on the dependent variable y
i dont know what they mean by describe

Answer 38

you can say that since x-2 is under the square root and there can be only non negative numbers under the square root x must be larger or equal 2

Answer 39

as well since the lowest value that you can get from the square root is 0 the minimum value in the range is -3
since the values of the square root can be high as much as we want there is no upper bound for the range

Answer 40

i dont know lol
what do they want from us :(

Answer 41

well i think it's more than enough choose whatever you want from it .. and write the domain and range

Answer 42

ill help you whenever you want ;)

Answer 43

not my dream i must say

Answer 44

as i told you im doing a degree on physics
and i think that i want stay in the academy doing researches..

Answer 45

what about you ?

Answer 46

ok so you have some different options
i see that you like animals .. do you have a pet ?

Answer 47

maybe it's better to message each other (here people can see)

Answer 48

so done with this question ?

Answer 49

:)