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Chemistry 14 Online
OpenStudy (anonymous):

If it were possible to have a 9.0 x 1023-atom sample of pure titanium, what would be the mass of this sample, in grams? .0140 g .0312 g 32.0 g 71.6 g

OpenStudy (anonymous):

9.0 x \[10^{23}\] /6.023 x \[10^{23}\] will give u no of moles

OpenStudy (anonymous):

and then multiply the no of moles with the atomic wt of titanium

OpenStudy (anonymous):

ans is 71.6

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