Question

Which of the following is a solution to the equation log 4 x + log 4 (x – 3) = 1 ?

Answer 1

I believe that I need to multiply it causing

log4 x^2 - 3x = 1

Or is that wrong?

Answers are

x = 6/5

x = –3

x = 4

Answer 2

log4 ((x^2 - 3x) = 1

so (x^2 - 3x = 4^1 = 4
x^2 -3x - 4 = 0
(x-4)(x + 1) = 0

x = 4 or -1

x=4 is correct

Answer 3

log of -1 does not exist

Answer 4

Ok let me get this straight

when we are in the part of

log4 (x^2 - 3x) = 1

we multiply 4 * 1 or is it 4^1? (either way it's 1, but would want to understand)

then we get

x^2 - 3x = 4

x^2 - 3x - 4

(x-4)(x+1)

x = 4

Correct?

Answer 5

ok the log is defined as the power that the base as to be taken to to get the number you are taking log of

eg

4^2 = 16
so log4 16 = 2

4 is the base, 2 is the log

Answer 6

working the other way

log4 16 = 2
4^2 = 16

Answer 7

Hmmmmm

so it's like the power of the other side?

EX:

log5 125 = 5

5^5 = 125

Answer 8

thats right

Answer 9

if we have variables inlvolved


log4 x = 2

then x = 4^2

Answer 10

this is 'taking logs out'

Answer 11

Ahhhhhh! Thanks, now I understand the question and now how to answer other questions!

Answer 12

good