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Engineering 16 Online
OpenStudy (anonymous):

How much electric charge must move through a load to release 50 J of energy when potential drop across the load is 120 V.

OpenStudy (anonymous):

Note that: \[U=\frac{ 1 }{ 2 }QV\] Where U is the energy in Joules given charge Q (coulombs) and V voltage in Volts. I'll let you take it from here.

OpenStudy (anonymous):

apply E=1\2 CV^2 Calculate value of C from Here

OpenStudy (anonymous):

Pardon me but E=1/2CV^2 is the energy on a charged capacitor not the energy expended in dropping a charge through a potential.

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