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Mathematics
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solve: 2^(2x+1) - 33(2^x) +16 = 0
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let \(y=2^x\) and substitute into your equation. you should end up with a quadratic in y. solve that, then find x.
0_o
remember that \(2^{2x+1}=2\times2^{2x}=2\times(2^x)^2\)
ah!
:)
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thank you so much
yw :)
maths is amazing 0_o
it's good when you get those "aha!" moments! :D
:)
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