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Mathematics 11 Online
OpenStudy (anonymous):

Suppose the lim as x->0 of [f(x)]/x equals to 5. What is the lim of f(x) as x->0?

OpenStudy (anonymous):

\[\lim_{x \rightarrow 0}\frac{f(x)}{5}=5\] The five is a constant, \[5*lim_{x \rightarrow 0}\frac{f(x)}{5}=5*5=\frac{5}{5}*lim_{x \rightarrow 0}f(x)\]

OpenStudy (anonymous):

\[\lim_{x \rightarrow 0} f(x)/x = 5. What is \lim_{x \rightarrow 0} f(x)?\]

OpenStudy (anonymous):

There are two cases where f(x) can exist. f(x) = x * g(x) such that lim_x->0 f(x) = 5 where the x's cancel out, or you have l'Hopital's rule where lim_x->0 f(x)=0 but lim_x->0 f'(x) = 5

OpenStudy (anonymous):

that first one should be lim_x->0 g(x) =5, I mistyped it.

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