Question

need help verifying please, still don't quite understand this one
(sin/1 - cos) - (1 - cos/ sin) = 2cot
It looks like I could cancel out the like terms but I'm not sure

Answer 1

\[\frac{b}{1-a}-\frac{1-a}{b}\] is some algebra. do that first

Answer 2

cross multiply first right?

Answer 3

it is less confusing than working with sines and cosines. then put them back in the end
i hope it is clear what i did , replace \(\sin(x)\) by \(b\) and \(\cos(x)\) by \(a\)

yes, "cross multiply" although i think i would say "add"

Answer 4

you will also need trig identities (sin^2(x) + cos^2(x) = 1

Answer 5

just do the algebra, totally ignore the trig
if you see \(a^2+b^2\) you can replace it by 1, but that is at the end
oh, what @VeritasVosLiberabit said

Answer 6

actually maybe you won't

Answer 7

okay so it would then be sin^2/ 1 - cos2?

Answer 8

find a common denominator