Question

how do I solve? archer releases an arrow from shoulder height of 1.39m arrow hits target 18m away. when target is removed, arrow lands 45 m away. find the maximum height of the arrow aloong its parabolic path.

Answer 1

U can use the equation of linear motion to solve this...:)

Answer 2

what is that equation? I think the answer is suppose to be 1.41m but didn't know how to get it

Answer 3

So you know three points
take the origin to be where the arrow is fired
one point is (18, 1.39) another is (45, 0) and another is (0, 0)

you need to find the equation of a curve when you know three points. I am trying to work this out :P

Answer 4

I have a diagram of a bullseye target with point A marked 8c. and I think that is where the arrow hits. Is this something you need to know?

Answer 5

do I need to know the shoulder height of archer?

Answer 6

yeah thats given as 1.39. your right that means your last point is 0, 1.39 not 0,0

Answer 7

I see I do have the shoulder height of 1.39m

Answer 8

isn't there an angle of releasing the arrow..

Answer 9

i dont think you need the angle

Answer 10

no angle given.

Answer 11

so by the questions own admission, the arrow flies in a parabola. The general equation for a parabola is y = ax^2 + bx + c where a b and c are just constants right?

Answer 12

what are a,b,c?

Answer 13

Ok the equation to solve this is given by @JamesWolf

Answer 14

I am thinking something is missing from the problem

Answer 15

i see the equation but what do I plug into equation

Answer 16

C will be 1.39

Answer 17

I am i correct @JamesWolf

Answer 18

i agree completely, without knowing the height of the target the parabola could be any of these