Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

Can some one explain how to solve this?

OpenStudy (anonymous):

OpenStudy (anonymous):

This sucks but here we go.

OpenStudy (anonymous):

chance of failing 0.17, so chance of success is .83

OpenStudy (anonymous):

To answer part a and b I would like to know their definition of unusual. Probably wouldn't be unusual that one would fail. But the probablility that both fail is 0.17*0.17

OpenStudy (anonymous):

part b. The probability that the system succeeds. It says only one needs to work for it to succeed. So this is one minus the probaility that both fail. So 1-(.17*.17)

OpenStudy (anonymous):

The last one we can setup an equation that is very similar to what we just did in part b.

OpenStudy (anonymous):

1-(.17)^2 where there is 2 components. that is what we did in part b

OpenStudy (anonymous):

1-(.17)^n = .9999 solve for n which is number of components

OpenStudy (anonymous):

Did you understand everything?

OpenStudy (anonymous):

ok so part a is no?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!