Question

can you solve plz this equation ?!!
in the pic below

Answer 1

x=0 i think

Answer 2

Is it square root or cubed root?

Answer 3

cubed root

Answer 4

@swissgirl plz help :)

Answer 5

hahahah I am trying to but too much going on at my end give me a few minutes

Answer 6

why did you removed the roots ?!!

Answer 7

Whoops that was wrong I used a non existant property to solve that. Wait let me do this again

Answer 8

lets call a = (2-x)^(1/3)
b = (2+x)^(1/3)

so we have
a+b = 4^(1/3)

raise both sides to the power of 3 and get :

a^3 + 3a^2b + 3ab^2 + b^3 = 4

but we know :
a^3 = (2-x)
and
b^3 = 2+x
so we get:

2-x +3a^2b + 3ab^2 + 2+x = 4
->
a^2b+ab^2 = 0
ab(a+b) = 0

so
a = 0 or b = 0 or a = -b
for a = 0 we get x = 2
for b = 0 we get x = -2
for a = -b we get 4 = 0 which is not true
so
x=2 or x = -2.

Answer 9

thanx a lot @swissgirl and @Coolsector

Answer 10

yw

Answer 11

Hahah i messed up and coolsector saved the day

Answer 12

:)