Question

An object is launched upward at 64 ft/sec from a platform that is 80 feet high. What is the objects maximum height if the equation of height (h) in terms of time (t) of the object is given by h(t) = -16t² + 64t + 80?
Round to the nearest foot.

Answer 1

graph the parabola :)

Answer 2

then find the maximum :)

Answer 3

or you could just use the formula for finding the vertex \((x=-{b\over2a})\) and find the x then plug that value of x into the equation and find y, which would be your maximum

so your max should be 144ft