5z > –45
Try dividing both sides by five
z>-9
Right
that won't do..it's inequality we're talking about..
transfer the -45 to the other side.. 5z + 45 > 0
@darkprince14 I don't understand your point. The purpose of this problem is to establish which values of z satisfy the inequality. It's like solving an equation for a variable, except that our solution may include a significant range of values rather than a set a finite number
get it's domain... it should be z> -9 then its domain would be z = ( -9, +infinity)
@L.T. so try substituting -9 to z.. It will be like this... 5(-9) > -45 -45 > -45 That won't do bcause -45 can't be grater than -45...
we're only finding points that may satisfy the inequality... it's a huge range though...
The symbol shows that z is greater than 9: nine isn't included!
@darkprince14
yeah..that's why i made it an open interval... sorry didn't see your point earlier...sorry for being so childish...
@L.T.
It's fine
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