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Help with functions?! f(x) = 3x^2-4 g(x)=x^2-3x-4 find (f/g)(-1)
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so where it says "f", put in everything after the equals sign for the f(x) function (hint: 3x^2 - 4) and then where it says g put in everything after the g(x) function (x^2 - 3x - 4)
so it just becomes the fraction of 3x^2-4 / x^2-3x-4, and then solve the fraction and multiply by -1?
you lilly, are a genius. absolutely spot on.
if it were f+g is it the same, just (3x^2-4) times (x^2-3x-4)?
that would be f TIMES g
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ok. THANKS!!
f + g is exactly as it looks (3x^2-4) + (x^2-3x-4)
ok, thanks again!
what about f^g ?
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