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\[\sqrt{8x + 5} = 3\sqrt{x}\]
square both sides to rid of the square roots
So it would be: 64x + 25 = 9 + x^2?
no 8x + 5 has a square root over it so think of it like a force field and you can only rid of it with a square thus depleting both, but doing no harm to the 8x + 5
same with the X on the other side
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So it would be 8x + 5 = 9x?
yup, then combine likes terms and presto
Thanks! Do you think you could help me with one more? Not sure whatg to do with thesee, why do they have the lines in front of them?: \[|x+2| = 3\]
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