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I=nE/nr+R solve for n Please help me!
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Is this the equation? \[I=\frac{nE}{nr+R}\]
yes!
First multiply both sides of the equation by nr + R to get rid of the fraction. Can you do that?
I(nr+R)=nE
Then multiply out the left hand side to get rid of the brackets.
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Inr+IR=ne
Now subtract Inr from both sides to brin all terms containing n to the right hand side.
n = IR(Ir - E) B) n = IR/Ir+E C) n = -R/Ir-E D) n = IR/E-Ir
We will arrive at one of these options. Please be patient :)
k im so tired
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IR=NE-Inr
nE*
\[IR=nE-Inr=n(E-Ir)\] \[n=\frac{IR}{E-Ir}\]
thank you!
You're welcome :)
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