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Find y" in terms of x and y by implicit differentiation. (x^3)+(y^3)=4^3
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I think the first would start out as 3y^2(dy/dx) so 3x^2+3y^2(dy/dx)=0
Dang, what am I doing wrong, the professor didn't really go over this rule in my class.
ok thats right carry on sorryyyyyyyyyyyyyy
so would the second derivative be 6x+6y(dy/dx)=0
ya right
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Okay then after that how would you put it in terms of x and y? I am guessing to start you would put all the y's on one side like this maybe? 6x=6y(dy/dx)
ya but 6x= -6y(dy/dx) => dy/dx = -x/y
but remember this is the second derivative
Now I am stuck, sorry.
why where????
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I am stuck on simplifying it down to terms x and y
ok ok see this
|dw:1350022221980:dw|
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