Question

find the value of y in the given expression : y=(1+cos2THETA)tanTHETA

Answer 1

answer it plssssss

Answer 2

answer it plsssssss

Answer 3

are you sure this is the whole questions. It seems like y could have any value
between -1 and 1

Answer 4

yes ..it is a board exam question

Answer 5

also is it cos^2(theta) or cos(2theta)?

Answer 6

no its not squared

Answer 7

given that y=(1+cos(theta))tan(theta), y can take any value between -1 and 1. unless you know what theta is.

Answer 8

it can also be written as y=sin(2theta), maybe that's what they are looking for, but that is not a value of y

Answer 9

=SIN2THETA
ITS BETWEEN 1 AND -1