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please help!!!! Solve for x: cos(X) + cos(2x) = -1
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DO YOU KNOW THE FORMULA OF cos(2x) ????
Here's a cheat sheet if you need it. http://tutorial.math.lamar.edu/pdf/Trig_Cheat_Sheet.pdf
what do you mean?
He means if you change cos(2x) to some function of cos(x), then you can more easily solve for cos(x).
x=-1/2 cos^(-1)(-1-cos(X))
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and another solution is x=1/2 cos^(-1)(-1-cos(X))
but what is x then??
\[\cos(x)+\cos(2x)=-1\] \[\cos(x)+\cos^{2}(x)-\sin^{2}(x)+1=0\] \[\cos(x)+2\cos^{2}(x)=0 ...since...1-\sin^{2}(x)=\cos^{2}(x)\] \[\cos(x)=0...or...1+2\cos(x)=0\] Can U find x from here ?
What interval are you solving over? There are four solutions between 0 and 2π.
yes i can solve x from here...thanks you guys for helping!!
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