solve for y in the first equation. x – 3y = –6 2x – 7y = 10
its one of these answers ; 1/3x+2 - 1/3x+6 -x+2 -1/3x +2
please help:) i don't want the answer i just want help
write the given equation in the form of y=mx+c
first, take x onto the right hand side.
so i think that you need to calcule the x from second equation and this resulted value of x you need just substitute in place of x in the first equation and in this way will get the y from the first equation
let me try
hope so much that is understandably
so if you need to calcule the x from second equation what will be the first step ?
assum to both sides 7y
so than what will get ?
don't i need to get y by itself? wouldn't it be - 2 on both sides?
because your exercise is to solve for y from the first equation ,yes ?
yes
so than you need to get a value of x from the second equation and this value of x will need to substitute in place of x in the first equation ok ?
ok
so than calcule please the first step how i have wrote it before little up what will get ?
2x-7y=10 subtract 7y on both sides and get 2x=3 divide by 2 on each side and get 1.5
why ? how can you subtracting from 10 the 7y ?
oh my word i'm confused, i got - 1/3x+6 as the answer is that correct?
please write it here step by step
adding to both sides 7y will get 2x=10+7y yes ?
so than from this how you will get the x ?
so do you like to continue it ?
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