Question

Solve the equation by completing the square.
x^2 + 6x − 14 = 0
x = (smaller value)
x = (larger value)

Answer 1

\(x^2 + 6x = 14\)
Take half the bx term , square it, and add the result to both sides:
\(\frac{1}{2}(6) = 3\) and \(3^2 = 9\). So
\(x^2 + 6x +9 = 14 +9\)
Now factor the left and simplify the right,
\((x+3)^2 = 23\)

Answer 2

x^2+6x+9 = 23?