Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

Two numbers are selected at random from set of the first 100 natural numbers. The probability that the product obtained is divisible by 3 is..

OpenStudy (anonymous):

I am not good at probability .. :(

OpenStudy (anonymous):

No problem..@Miyuru You can learn it...Its interesting

OpenStudy (anonymous):

Hmm yeah @AbhimanyuPudi I too posted one see whether u can..:D

OpenStudy (anonymous):

@JakeV8

OpenStudy (anonymous):

@hartnn

OpenStudy (anonymous):

@hero @experimentX @TuringTest @asnaseer @Chlorophyll

OpenStudy (turingtest):

I am also bad a probability. @Zarkon and @satellite73 are probability gurus.

OpenStudy (anonymous):

@Algebraic! @ganeshie8

OpenStudy (anonymous):

Fine..never mind @TuringTest

OpenStudy (experimentx):

for a number to be divisible by 3, AT LEAST ONE of the number has to be divisible of three.

OpenStudy (anonymous):

Yes...

OpenStudy (anonymous):

Are the numbers distinct?

OpenStudy (experimentx):

there would be 33 numbers ... so the numbers that is not divisible by 3 is ... 67 ---------------------------------- find the probability that two numbers are not divisible by 3 ... subtract from 1

OpenStudy (anonymous):

Yes ofcourse distinct @MrMoose

OpenStudy (anonymous):

You mean 1 - (67 C 3) / (100 C 2) ? @experimentX

OpenStudy (anonymous):

*2...in the numerator..not 3

OpenStudy (experimentx):

|dw:1350148887494:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!