Question

(x+6)(x-9)=5

Answer 1

X^2-3x-59=0

Answer 2

9 * 6 = 54 not 59

Answer 3

i distrube them x^2-9x+6x-54=5
x^2-3x-59=0

Answer 4

k.. wat mor

Answer 5

im not sure is it b^-4ac the formual

Answer 6

b^2 -4ac formula for discriminant

Answer 7

yeah... of course b^2 - 4ac

Answer 8

Use foil method

Answer 9

after u use foil u should get
x^2 -3x-54

Answer 10

(x+6) (x-9) =0

Answer 11

Try -6 or 9
and substitute it for x

Answer 12

1. Rewrite the given equation as a quadratic equation:
(x+6)(x-9)=5
x(x-9) + 6(x-9) = 5
x^2 - 9x + 6x - 54 = 5
x^2 - 3x - 54 = 5
x^2 -3x - 54 - 5 = 0
x^2 -3x - 59 = 0

2. Use the quadratic formula to find x where a = 1, b = -3, c = -59
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
\[x = \frac{3 \pm \sqrt{(-3)^2 - 4(1)(-59)}}{2(1)}\]

You should be able to finish from there.

Answer 13

ok im back. wow thank you for your replys. So, now i did the formula \[3\pm \sqrt{-227}/2\]

Answer 14

Your radicand should be positive.

Answer 15

is the answer \[\left(\begin{matrix}3\pm 7\sqrt{5}\\ 2\end{matrix}\right)\]