Which of the following is the correct equation for this function?
(will attach graph in a sec as well as the answer choices!)
***Please explain!! idk how to do this. thanks!! :D
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OpenStudy (anonymous):
here is the graph :)
OpenStudy (anonymous):
roots
OpenStudy (anonymous):
here are the answer choices
A,B,C,D from top to bottom
thanks!!
OpenStudy (anonymous):
what do u mean by roots?
OpenStudy (anonymous):
\[x _{1},and,x _{2}\]
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OpenStudy (anonymous):
like -1 and 3??
OpenStudy (anonymous):
so use them in the root formula
\[y=(x-x _{1})(x-x _{2})\]
OpenStudy (anonymous):
the other point i use is this??
(1,4)
??
OpenStudy (anonymous):
so i get this??
4=(1-(-1))(1-3)
4=(1+1)(-2)
4=(2)(-2)
4=-4
?? wait that doesn't seem right..
OpenStudy (anonymous):
so first star with the roots substitution
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OpenStudy (anonymous):
hold on like this??
y=(x-(-1))(x-3)
OpenStudy (anonymous):
sorry i forgot a
in
\[y=a(x-x _{1})(x-x _{2})\]
OpenStudy (anonymous):
so y=a(x-(-1))(x-3)
??
OpenStudy (anonymous):
and i get y=a(x+1)(x-3)
??
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
so do i solve for a now?? :O by plugging in values??
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
okay so i do this?
y=a(x+1)(x-3)
4=a(1+1)(1-3)
4=a(2)(-2)
4=a(-4)
divide both sides by -4
and i get this???
-1=a
??
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
so this is my answer??
y=-(x+1)(x-3)
so my answer is D. y= -(x+1)(x-3)
???
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