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Mathematics 19 Online
OpenStudy (anonymous):

why does dp/sqrt(P)=sqrt(P)

OpenStudy (anonymous):

\[\frac{ dp }{ \sqrt{p} }=\sqrt{p}\] Is that the question?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

because dp/sqrt(P)=k*dt, but i dont understand how the left part after integration comes about to just sqrtP

OpenStudy (anonymous):

\[\frac{ 1 }{ \sqrt{p} }=p^{-1/2}\]

OpenStudy (anonymous):

thanks

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