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Solve by extracting roots: (x+2)^2-7=0
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add 7 to both sides... what equation you have now?
\[x+2=\pm \sqrt{7}\]
That's correct. Just need to subtract both sides by 2 to solve for x.
\[x=\pm \sqrt{7}-2\]
\[x=-2\pm \sqrt{7}\times \sqrt{-2}\]
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I mean sqrt(-2)...
I was looking at examples in the book and it says that you are to multiply sqrt (-2) over sqrt (-2)
That could be for a different problem not really similar to your current problem. Because right now, it is already correct without the multiplication of sqrt(-2).
Do you know also that \[\sqrt{-2}=2i\] which is am imaginary number.
yes
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Okay then. Glad to be of some help tonight.
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