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Find F^-1(x) f(x)=ln(x+3)
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is this because ln = e that we have e^(x+3)
or is it because the inverse of ln is e
im kinda confused on that one
\[f(x)=y=\ln (x+3)\] Interchanging x and y to find the inverse: \[x=\ln (y+3)\] Therefore \[e ^{x}=y+3\] \[f ^{-1}(x)=e ^{x}-3\]
Ok I understand now ty
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