Question

If m is an odd integer and n an even integer, which of the following is definitely odd?
a..(2m+n)(m-n) b.. (m+n^2)+(m-n^2) c..m^2+mn+n^2 d... m+n

Answer 1

is your second sentence correct sauracshakya?

Answer 2

U know odd number + odd number is even number
odd number + even number is odd number
odd number times odd number is odd number
odd number times even number is even number

Answer 3

i knew it ....but as you wrote odd +even=even is not correct
its odd

Answer 4

correct now

Answer 5

Thanx @cwrw238

Answer 6

yw

Answer 7

wt do u think wts the answer

Answer 8

m=3,n=2 we can substitute to see the answer

Answer 9

What about d

Answer 10

there is conflict in between c and d

Answer 11

Nope a and d

Answer 12

c is even

Answer 13

no a is not odd :- even times odd = even

Answer 14

Yes not a

Answer 15

yea d is definitley odd

Answer 16

yes a is not odd definately it is even

Answer 17

im confused about c is it even or odd ...accc to me it is odd

Answer 18

reply gys

Answer 19

m^2 is odd
nm is odd
and n^2 is even

odd + odd + even = even

Answer 20

nm can not be odd ...take an example 2*3=6 and it is even

Answer 21

so in this ...c and d both are odd ...,,so its finally done

Answer 22

lets look at it again to make sure - i don't trust myself today

Answer 23

m^2 is odd
mn is even

even + odd = odd

n^2 is even
odd + even = odd

yes c is odd

Answer 24

i was sure about it but in tcs site they did'nt give another option if both answere are correct ...but now i think that there was some mistake

Answer 25

yes - thats part of problem you automatically think theres only one solution
as u say there could have been mistake in the question.