Question

h5p2.....im lost on this....give me step by step how you do this please....What is the minimum value of VDD (in Volts) that we must supply to keep the transistor in the region of saturated operation?

Answer 1

what are ur values given.............give the cumplete question

Answer 2

dude answer something between 2 to 7

Answer 3

try it

Answer 4

i guess you got it

Answer 5

not yet

Answer 6

vdd=5.5. just try it

Answer 7

i got it...VIN-VOUT greater or equall ti VT...VT=2.0
6.1-3.6=2.5
5.4-2.9=2.5
6.8-4.2=2.6
VIN-VT
6.8-2=4.8
VDD=4.8

Answer 8

is you check. i though it must be corect

Answer 9

vdd is 5.5 for me. other vin is diferent

Answer 10

ok right for me....thanks.....H5P1.....whats the step by step solution 1, 2, 3

Answer 11

-.5,8000,0.093 is the answere

Answer 12

step by step solution

Answer 13

,
we have to find max Vin ;
to find Vin let us apply kvll to the input loop
Vin - Vgs+1 =0;
ie, Vin = Vgs-1 ...............................(eqn1)
now the unknown parameter is Vgs, hence to find it
lets apply KVL to external loop :
1-Ids*R-Vds+1=0 ,
further substituting the value of Ids = k/2 *(Vgs-Vt)^2 in the above equation and solving the quadratic equation we will get,
Vds = 0.593, -0.84 : as Vds needs tobe +ve hence neglecting he -ve term we have
Vds = 0.593
and we know Vds = Vgs-Vt
ie Vgs = Vds+Vt
therefore, Vgs = 0.593+0.5=1.093
and substituting the above valuw in eqn1 we have
Vin=1.093-1=0.093

Answer 14

@benzo : In saturation: iDS=K/2*(vGS-VT)2, and since here vGS is vIN-vOUT, then
iDS=K/2*(vIN-vOUT-VT)2
Q2
vOUT=

Answer 15

vOUT=iDS*RS

Answer 16

thanks lab and hw 100%

Answer 17

i get the vout for sorce flower small signal but its doesn't work what you vout for source flower small signal

Answer 18

vi=0.0009V what is the incremental output vo?
also Gain

Answer 19

gain=0.9498

Answer 20

and vo?

Answer 21

yes vo=0.9498

Answer 22

Wont that conclude a gain of 1055?

Answer 23

Bro Gain is .94 vo=?

Answer 24

Q1
vOUT = iDS*RS
vout/vin = ϑvOUT/ϑvIN @ VIN = RS * ϑiDS/ϑvIN = RS * (1/RS + 1/(K*RS
2)*(-2K*RS/(2d))
where d=sqrt(1+2K*RS*(VIN-VT)))
Simplifying the expression above will give:
vout/vin = (1-1/d) à vout=vin*(1-1/sqrt(1+2K*RS*(VIN-VT))))
Q2
For K=2 [A/V2], VT=2V, RS=16Ω, VIN=6.5V and vin=0.001 V,
d=19.925 and thus vout/vin = (1-1/d) à vout=0.001*(1-1/19.925)=0.001*0.9498
à vout = 0.0009498 V
Q3
We've already found voltage gain solving for Q2.
vout/vin = (1-1/d) = 1-1/19.925 = 0.9498
You can see that source follower has a voltage gain slightly less than 1.

Answer 25

vo= 0.0009498 gives X (wrong)

Answer 26

for each value each answer

Answer 27

for VIN = 6.4, 6.9 and 5.9?