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subtract 8x/x+1 - 3/x+1 please help ?
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Is this like:\[\frac{ 8x }{ x+1 } - \frac{ 3 }{ x+1 }\]
yes :)
ok, well, it looks like lots of "stuff", but if you think about when you were just doing basic subtraction or addition with normal (non-algebra) fractions, if they had a common denominator, you could add or subtract directly... like 4/7 + 1/7 = 5/7
here your common denominator is x+1 But you can still add the stuff on top, and combine it all over the common denominator, x+1
(well, it's subtracting here, not adding, but same idea)
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\[\frac{ 8x }{ x+1 } - \frac{ 3 }{ x+1 } = \frac{ (8x-3) }{ x+1 }\]
Thank you
you are welcome... glad to help! Hope that made sense!
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