Calc: Find the area of the region between the curves y=sin(pix/2) and y=x (picture)
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OpenStudy (anonymous):
OpenStudy (anonymous):
OpenStudy (anonymous):
as you can see in the pic, there are two regions that we'd need to calculate to get the total area between these curves, but I think it'd be easier to find the area of one and then double it
OpenStudy (anonymous):
so lets find the area of the region in the first quadrant. it looks like they intersect at 0 and 1 so those will be out limits of integration.
OpenStudy (anonymous):
our*
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OpenStudy (anonymous):
the sine function is on top of y = x so we'll find the area of the top function and then subtract the bottom one to find the area between
OpenStudy (anonymous):
for point of intersection how did you get 1? did you get them equal to each other? if we did not have an exact graph to look at
OpenStudy (anonymous):
so we integrate:
\[\int\limits_{0}^{1}(\sin(\frac{ \pi x }{2}) - x)dx\]
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
ok let me try that real quick and see what i get
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OpenStudy (anonymous):
- cos pi -1/4
OpenStudy (anonymous):
-cos(pi/4)-1/2
OpenStudy (anonymous):
I'm getting a different answer, can you show me how you integrated?