Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

Calc: Find the area of the region between the curves y=sin(pix/2) and y=x (picture)

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

as you can see in the pic, there are two regions that we'd need to calculate to get the total area between these curves, but I think it'd be easier to find the area of one and then double it

OpenStudy (anonymous):

so lets find the area of the region in the first quadrant. it looks like they intersect at 0 and 1 so those will be out limits of integration.

OpenStudy (anonymous):

our*

OpenStudy (anonymous):

the sine function is on top of y = x so we'll find the area of the top function and then subtract the bottom one to find the area between

OpenStudy (anonymous):

for point of intersection how did you get 1? did you get them equal to each other? if we did not have an exact graph to look at

OpenStudy (anonymous):

so we integrate: \[\int\limits_{0}^{1}(\sin(\frac{ \pi x }{2}) - x)dx\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ok let me try that real quick and see what i get

OpenStudy (anonymous):

- cos pi -1/4

OpenStudy (anonymous):

-cos(pi/4)-1/2

OpenStudy (anonymous):

I'm getting a different answer, can you show me how you integrated?

OpenStudy (anonymous):

|dw:1350284448928:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!