Calc: Find the area of the region between the curves y=sin(pix/2) and y=x (picture)
as you can see in the pic, there are two regions that we'd need to calculate to get the total area between these curves, but I think it'd be easier to find the area of one and then double it
so lets find the area of the region in the first quadrant. it looks like they intersect at 0 and 1 so those will be out limits of integration.
our*
the sine function is on top of y = x so we'll find the area of the top function and then subtract the bottom one to find the area between
for point of intersection how did you get 1? did you get them equal to each other? if we did not have an exact graph to look at
so we integrate: \[\int\limits_{0}^{1}(\sin(\frac{ \pi x }{2}) - x)dx\]
yes
ok let me try that real quick and see what i get
- cos pi -1/4
-cos(pi/4)-1/2
I'm getting a different answer, can you show me how you integrated?
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