Georgia has only dimes and quarters in a bag. She has a total of 18 coins that are worth $3. How many more dimes than quarters does she have?
let D = the number of dimes let Q = number of quarters we know from the problem that the number of coins is 18 so we can safely say that D + Q = 18
yeah.... i got that far then i did .25q + .10d = 3.00 and well.... it doesn't work.
try setting D = 18 - Q and then plug D into ^ equation
i did, i got some odd equation and since it's asking how many, an eqation of any sort cannot be an answer
lets work through it step by step if I let D = 18-Q and then plug in we get .25Q + .10(18-Q) = 3.00
then we distribute the .10 so .25Q - 1.80 - .10Q = 3.00
we can then combine like terms .15Q -1.80 = 3.00
.15q - 4.8*
=*
no wait i made a mistake it should be .25Q + 1.80 -.10Q = 3.00 so you were right .15Q = 1.2
and once you find a value for Q you can plug that into D + Q = 18 to find D
and then take the difference D - Q to find how many more dimes than quarters there are
myeh -.- i did the same thing and got it wrong, with you i got it right myeh myeh myeh! jubjub! i hate math >.> anyway thanks
np i made a mistake too
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