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help on derivatives(slopes). Will post question and my solution.
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Its asking for 2 equations...so 2 slopes? anyway... y = x^2 + x ; (2,-3) y' = 2x + 1 m = 2x + 1 m = 2(2) + 1 m = 5 y - y1 = m(x-x1) y + 3 = 5(x-2) y = 5x - 10 - 3 y = 5x - 13 <-- (1) But when i used (1) in my graphing calculator to double check, it is way off. why? and how would you get it.
If 5 is really the slope of the first equation, would it be the smaller or the larger value?
Sorry, I thought I knew but I don't :(
tangent line is unique
okay...
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What did your graph look like. Could you draw it?
|dw:1350267510236:dw|
Oh my bad. Check your original y coordinate. It doesn't work
hmm |dw:1350267513084:dw| my drawing is sumthing like ths
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