Ask your own question, for FREE!
Chemistry 14 Online
OpenStudy (anonymous):

Fe+S8 =>?? Predicting products

OpenStudy (anonymous):

what charge is the iron present (II or III)?

OpenStudy (anonymous):

Assuming iron's charge is (II), and that you mean 8S for an easier time balancing with S. Then the reaction of heating up iron + sulfur would be: 8Fe + 8S --> 8FeS but simply coefficients would just be: Fe + S --> FeS

OpenStudy (anonymous):

@Sheng Thanks! I have another question. Do you mind answering?

OpenStudy (anonymous):

go for it

OpenStudy (anonymous):

In the equation, Na+N2, it predicts that Na3N is its unbalanced product. Why is there only one N in the product when there is 2 in the first equation? @Sheng

OpenStudy (anonymous):

because it is "unbalanced"

OpenStudy (anonymous):

What do you mean? @Sheng

OpenStudy (anonymous):

What I mean is, when you first solve the equation, how do you come up with Na3N before balancing it?

OpenStudy (anonymous):

Oh, nitrogen has an oxidation number of -3, while sodium has an oxidation number of +1 to make a neutral compound of sodium and nitrogen, you need 3 sodiums (+1x3) to balance with 1 nitrogen (-3) 3-3 = 0.

OpenStudy (anonymous):

But how do you come up with 1 N in Na3N? @Sheng

OpenStudy (anonymous):

because the compound doesnt need another nitrogen, it's already satisfied the octet and is a neutral compound

OpenStudy (anonymous):

Why do you get rid of the 2 from the N on the original equation? What happens to the 2?

OpenStudy (anonymous):

ok to make this simpler to understand lets just take your unbalanced original equation and balance it: Na + N2 --> Na3N (unbalanced) 2 nitrogens on 1 side, 1 on the other, 3sodiums on 1 side, 1 on the other 6Na + N2 --> 2Na3N here you see, 6 sodiums on both sides, 2 nitrogens on both sides

OpenStudy (anonymous):

Sorry for the stupid questions. This is really hard for me

OpenStudy (anonymous):

@Sheng So the original equation already makes Nitrogen diatomic?

OpenStudy (anonymous):

nitrogen, oxygen, hydrogen are all diatomic elements they will always exist in a diatomic form

OpenStudy (anonymous):

Okay so the original equation already takes care of making it a diatomic ?

OpenStudy (anonymous):

@Sheng

OpenStudy (anonymous):

yes you'll only ever see N2 in equations when talking about just nitrogen

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!