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d^2y/dx^2 +19dy/dx +90y =0 The solution can be written in the form y=C1f1(x) +C2f2(x) with f1(x)= ? and f2(x)= ?
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I'm getting that f1 should be e^(-9x) and f2 should be e^(-10x) which is not correct
try without the minus signs
then you have 9 + 10 = 19, and 9 x 10 = 90
no your quite right sorry
nevermind for some reason webwork wasn't taking my answer but it finally did. Thanks for your help anyways :)
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auxillary equation will be (J + 9)(J + 10), making the answer C(e^-9x) + D(e^-10x) with C and d constants
yeah sorry
Just learning about this method myself atm. :)
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