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x^2+4x-5=0 is that 1, -4, 5, 4
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i thought it was 1
i assume you what are the zeroes of this function first factor this can u do that?
is it like putting them together i have no clue??
factor x^2 + 4x - 5 = (x + 5)(x - 1) = 0 x-1 = 0 , x = 1 yes 1 is a root
x+ 5 = 0 x = -5 is the other root
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I think the question is asking, which of the following are the roots of the given equation.
yes - so your answer is 1 teamjake
ok i just wanted to check thanks
yw
if there was an equation like x^2+x-6=0 i got -1 cause i did factor and it was -1 did i do it right?
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i thought i did
factors of this (x + 3)(x - 2)
the +x comes from 3x - 2x
zeros of this re 2, -3
so -6
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