The figure shows a triangular wooden frame ABC. The side AD of the frame has rotted and needs to be replaced.
What is the length of the wood that is needed to replace AD? 8.1 inches 6.2 inches 5.9 inches 7.4 inches
5.992
how?
tan30=DB/BC and tan45=AB/BC. tan45=1 and tan30=1/sqrt(3). tan45-tan30=1-1/sqrt(3)=0.423. Now, Substituting tan45 as AB/BC and tan30 as DB/BC. Therefore, (AB-DB)/BC = 0.423 But, AB-DB =AD and by multiplying BC on both sides, we get, AD = 0.423*BC , i.e. (0.423*14)inches = 5.922. Hope thats not confusing :)
no not at all, can you help me with another question.
You know, that AB=BC (because there is angle ACB=45degree, BAC=45degree). That's mean that the triangle is isosceles). So, AB=BC=14in. Also, let's say that BD is x, than DC=2x (because the hypotenuse is twice the length of the shorter side) Finally, acorrding to the Pythagorean theorem: \[x ^{2}+14^{2}=(2x)^{2}\] \[x ^{2}+196=4x ^{2}\] \[3x ^{2}=196|:3\] \[x \approx8.0.8\] AD=AB-BC=14-8.08=5.91
thanks so much :)
@Kamille Thats much simpler and better.
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