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Write the equation of the line that passes through (–3, 4) with a slope of 2 in point-slope form. y – 4 = 2(x + 3) y + 4 = 2(x – 3) y + 3 = 2(x – 4) y – 3 = 2(x + 4)
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Hint: Point-Slope form. y - y1 = m(x - x1) (x1, y1) m = slope
so y – 3 = 2(x + 4) @ jazy
Not quite. What are your x and y values in the given point?
-3
That is your y value: (x, y) (-3, 4) Okay, so in point-slope form: y - y1 = m(x - 1) Substitute -3 and 4 into the corresponding x1 and y2.
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What do you get? Also, remember that two negatives(-) equal a positive(+). (-)(-) = (+)
y + 3 = 2(x – 4)
waitt
-3 is the x-value
y – 4 = 2(x + 3)
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Right! (:
thanks.. can u help me some more
I'll try to help, I have to go soon though.
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