Question

FLVS problem and i have no clue how to finish this problem
Solve 4x2 = 12x + 40.

Answer 1

4x2 = 12x + 40

4x^2 - 12x - 40 = 0

Get rid of 4 by taking commons

4(x^2 -3x - 10) = 0

Divide 4 on both sides

(x^2 -3x - 10) = 0



Now factor:

x^2 - 3x -10 =0

x^2 -5x + 2x - 10 = 0

take commons:

x(x-5) +2(x-5) = 0

(x+2)(x-5) = 0

solve them for Zero:

x = -2

x = 5

Answer 2

taking 4 common on both sides..
x^2 = 3x + 10
x^2 - 3x - 10 = 0
now factorize
x^2 -5x + 2x - 10 = 0
x(x-5) +2(x-5) = 0
(x-5)(x+2)=0
Either (x-5)=0 this gives x=5
Or (x+2)=0 this gives x= -2

Answer 3

@iveymarie got it..??

Answer 4

Thankyou @Kashan and @Skysthelimit I was getting so stuck at the factoring part!(:

Answer 5

@iveymarie your welcome!! I'm in flvs to