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Mathematics 8 Online
OpenStudy (anonymous):

find dy/dx of y=x√(x^2 + 1)

zepdrix (zepdrix):

derivative? \:D/ Hmmmmm looks like product rule huh huh? :D Confused on where to start?

OpenStudy (anonymous):

yes. square roots always mess with me ):

zepdrix (zepdrix):

Change your square root to a fractional exponent before you start this one! :) Will make it a little easier to get through. What is a square root in fraction form? :D

OpenStudy (anonymous):

sooo \[y=x(x^2+1)^\frac{ 1 }{ 2 }\]

zepdrix (zepdrix):

K looks good :D Now product rule time, yayyyy\[y'=(x)'(x^2+1)^{1/2}+x[(x^2+1)^{1/2}]'\]

OpenStudy (anonymous):

oh. well thats alot easier than i thought! haha thank you (:

zepdrix (zepdrix):

hah :D

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