calculus question!
find the points at which the graph of the equation has a vertical and or horizontal tangent line.
5x^2+8y^2+10x+48y+8=0

Question

calculus question! 
find the points at which the graph of the equation has a vertical and or horizontal tangent line.
5x^2+8y^2+10x+48y+8=0

anonymous · Answer

A horizontal tangent line is going to be where the slope is equal to zero, so first thing to do is find the slope.

anonymous · Answer

okay

anonymous · Answer

so first find the derivative then?

anonymous · Answer

Exactly.

anonymous · Answer

So  you'll need to get y apart from everything first, and take the derivative. Set that equal to zero, and solve for x.

anonymous · Answer

For a vertical tangent, think of what the slope of a vertical line is.

anonymous · Answer

so solve by implicit differentiatioN?

anonymous · Answer

yes?

anonymous · Answer

I should have looked closer, but this is an ellipse...I missed one of the Ys.

anonymous · Answer

ok

anonymous · Answer

so this means?

anonymous · Answer

So this means I'm a dork and shouldn't have jumped in so quickly...sorry. :P

anonymous · Answer

ok thanks