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calculus question! find the points at which the graph of the equation has a vertical and or horizontal tangent line. 5x^2+8y^2+10x+48y+8=0
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A horizontal tangent line is going to be where the slope is equal to zero, so first thing to do is find the slope.
okay
so first find the derivative then?
Exactly.
So you'll need to get y apart from everything first, and take the derivative. Set that equal to zero, and solve for x.
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For a vertical tangent, think of what the slope of a vertical line is.
so solve by implicit differentiatioN?
yes?
I should have looked closer, but this is an ellipse...I missed one of the Ys.
ok
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so this means?
So this means I'm a dork and shouldn't have jumped in so quickly...sorry. :P
ok thanks
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