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Mathematics 14 Online
OpenStudy (anonymous):

calculus question! find the points at which the graph of the equation has a vertical and or horizontal tangent line. 5x^2+8y^2+10x+48y+8=0

OpenStudy (anonymous):

A horizontal tangent line is going to be where the slope is equal to zero, so first thing to do is find the slope.

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

so first find the derivative then?

OpenStudy (anonymous):

Exactly.

OpenStudy (anonymous):

So you'll need to get y apart from everything first, and take the derivative. Set that equal to zero, and solve for x.

OpenStudy (anonymous):

For a vertical tangent, think of what the slope of a vertical line is.

OpenStudy (anonymous):

so solve by implicit differentiatioN?

OpenStudy (anonymous):

yes?

OpenStudy (anonymous):

I should have looked closer, but this is an ellipse...I missed one of the Ys.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so this means?

OpenStudy (anonymous):

So this means I'm a dork and shouldn't have jumped in so quickly...sorry. :P

OpenStudy (anonymous):

ok thanks

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