Question

Two blocks of masses m1 and m2 are placed on a table in contact with each other as shown in the figure below. The coefficient of kinetic friction between the block of mass m1 and the table is μ1, and that between the block of mass m2 and the table is μ2. A horizontal force of magnitude F is applied to the block of mass m1. We wish to find P, the magnitude of the contact force between the blocks.

What is the net force on the system of two blocks? (Use any variable or symbol stated above along with the following as necessary: F, P, and g.)

Fnet = What??? (It has to have a F, P, and g) in

Answer 1

this question replies a clear-cut understanding of free-body diagrams and friction.

Answer 2

can you tell me specifically where are you facing trouble. It'll be more convenient that way.

Answer 3

try\[F _{net} = 0\]

Answer 4

can you send me the link ?

Answer 5

fnet will depend on whether F > total friction or not

Answer 6

look, if Fnet > u1m1g + u2m2g , then Fnet = F - u1m1g - u2m2g, otherwise F = 0

Answer 7

No ,I said, Fnet = F - ( u1m1g + u2m2g ), While considering the system we don't take iternal forces as they cancel each other.

Answer 8

if not that then 0 must work. Try leaving the blank as blank

Answer 9

ok lemme see. umm maybe we can

Answer 10

*sigh* try (m1+m2)a . by the way, can you upload the pic of the complete question statement before the options are given ?

Answer 11

wait. .

Answer 12

try Fnet = F - u1m1g - P

Answer 13

you checked the writng style , etc ? Don't lose hope , maybe this blank is bad, let's check the others.

Answer 14

... sorry . I'll contact you later with suggestions.

Answer 15

try Fnet = u1m1g

Answer 16

oops , I meant Fnet=F -u1m1g

Answer 17

initially , there won't be any contact so P = 0