Question

is this correct.

Answer 1

\[\sqrt{u} + \sqrt{4-u}\]

Answer 2

domain is x is greater than = 0

Answer 3

for \(\sqrt{f(x)}\) , domain is f(x) > 0
so for
\(\sqrt{4-u}\)
domain = ?

Answer 4

sorry , domain is f(x) \(\ge\) 0

Answer 5

greater than equal to 4 ???

Answer 6

\[\ge4\]

Answer 7

4-u \(\ge\) 0
now ?

Answer 8

u\[\ge4\]

Answer 9

no, check for yourself, if u take 5, which is > 4
it will make \(\sqrt{4-u}=\sqrt{-5}\), so u\(\ge\)4 , is not correct

4-u \(\ge\)0 \(\implies\)u\(\le4\)
got this ?

Answer 10

yes

Answer 11

now the domain for \(\sqrt u\) is easy, it would be ?

Answer 12

u>/0 ??

Answer 13

yes,
so u have
\(u \ge 0 ,u\le4\)
overall, u get
\(0\le u\le4\)
got this ?

Answer 14

that would be your domain

Answer 15

in word, 'u taking values from 0 to 4, both inclusive'

Answer 16

still any doubts ?

Answer 17

how would the interval notation be ?

Answer 18

that would be correct

Answer 19

\[\left[ 0,4 \right]\]

Answer 20

interval notation [0,4]

Answer 21

is that correct ?

Answer 22

you are \(\huge \color{red}{\checkmark}\)

Answer 23

ok thanks

Answer 24

welcome ^_^

Answer 25

few more to go. help me out ok?