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2y^3+4x-ycosx=14, find an equation of the tangent line at P (0, 2) Would I have to take the derivative of this equation and plug in x in order to get the tangent line?
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find dy/dx and plug in your x and y values to get the slope. A point on the line is just the given point...
you'll need to use implicit differentiation to find dy/dx
so pretty much just solve for dy/dx and then plug in the points and then put the equation into point slope in order to get an equation of the tangent line?
yep.
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