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r^2=2csc2theta convert the polar equation to rectangular coordinates
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is that \[r^2=2\csc(2\theta)\]or\[r^2=2\csc^2\theta\]?
the first one \[r ^{2}=2\csc2\]\[r ^{2}=2\csc2\]
its suppose to be a theta in the end but idk its not showing
All you need is the fact that \[x = rcos \theta\]\[y = rsin \theta\]
but dont i need to change the csc into 1/sin?
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Well, that too. All I wanted was to stress the importance of those equalities somewhat :)
yes, and that\[\csc(2\theta)=\frac1{\sin(2\theta)}=\frac{\cancel2}{\cancel2\sin\theta\cos\theta}\]
@TuringTest \[*2\csc(2\theta)=\frac{2}{\sin(2\theta)}=\frac{\cancel2}{\cancel2\sin\theta\cos\theta}\] ;) Just sayin'
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