Not looking for answer, just walk through of which double angle formula to use. SinX=Cos2X
the one that leaves everything in terms of sine and a constant
cos^2x-sin^2x?
no, that one has a cosine in it...
oh soorry dyslexic, thought it said and cosine. so 1-2sin^2x
yeah :)
sinx / 2sin^2x = 1 1 / 2sinx = 1
whoa there? what did you do?
sinx=1-sin^2x
moved 2sin^2 x to the right side
left*
how, by division? if so you did the algebra wrong
oh, I see. I forgot to type the negative sign
you divided?
yes
if you divide both sides by 2sin^2x you get cscx=csc^2x-1 that doesn't really help us... try addition to get the everything on the left hand side
Might I suggest removing confusion by replacing all instances of sin x with, say, u, to make it look more algebra-y? :)
sorry, you would get 1/2cscx=1/2csc^2x-1
That's not how it is shown from previous examples. there's no addition
@terenzreignz yeah I was gonna get to that when we got it =0 to show that it looks quadratic, but you could of course do it now as well :)
@immings Previous example does not matter. all problem,s are different. I'm telling you to us addition (and subtraction) to get everything on the left hand side
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